Article ID: 197449
Article Last Modified on 3/14/2005
Dim cn As New ADODB.Connection
Dim cm As New ADODB.Command
Dim rs1 As New ADODB.Recordset
Dim rs2 As ADODB.Recordset
Dim rs3 As New ADODB.Recordset
cn.Open "DSN=Pubs;UID=<username>;PWD=<strong password>;"
On Error Resume Next
cn.Execute "drop procedure dbo.sp_AdoTest"
cn.Execute "create proc sp_AdoTest ( @InParam int ) as " & _
"select * FROM Authors WHERE State <> 'CA' " & _
"return @InParam + 10"
cn.Execute "drop procedure dbo.sp_AdoTest2"
cn.Execute "create proc sp_AdoTest2 as " & _
"select * FROM Authors WHERE State <> 'CA' " & _
"return 10"
Set cm.ActiveConnection = cn
cm.CommandType = adCmdStoredProc
cm.CommandText = "sp_AdoTest"
cm.Parameters.Refresh
cm.Parameters(1).Value = 10
Set rs1 = cm.Execute
Debug.Print cm.Parameters.Count
At this point, the Parameters collection for the command object has two
objects, and you can reference them as you would normally. However, consider
the following code, which destroys (resets) the Parameters collection: cm.CommandText = "sp_AdoTest2" cm.Parameters.Refresh Set rs1 = cm.Execute Debug.Print cm.Parameters.CountAt this point, the Parameters collection has been reset to contain only one Parameter object. However, the original Recordset (rs1), which has not been closed or released, still has a reference to an internal buffer that stores the value of each parameter that was originally created. When the original recordset is closed, it attempts to release the buffer. However, the second recordset's Parameters collection may be using the same memory location for its own buffers, and if both recordsets are trying to release the same memory location, you may receive an Access Violation.
rs2.Close rs1.Close cn.CloseThe Access Violation has been confirmed to occur (at random intervals) when using a forward only cursor with a parameterized stored procedure using the OLE DB Provider for ODBC to the SQL Server ODBC Driver. It may occur with other ODBC Drivers or OLE DB Providers as well.
Keywords: kbdatabase kbprb KB197449