Article ID: 190446
Article Last Modified on 12/4/2007
IP Address = 010.100.004.022 Subnet Mask = 255.255.000.000
IP Address 00001010 01100100 00000100 00010110
Subnet Mask 11111111 11111111 00000000 00000000
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Result 00001010 01100100 00000000 00000000
The AND result in decimal is 010.100.000.000 Therefore, addresses
010.100.000.001 - 010.100.255.254 have access to the LU.
IP Address = 010.100.004.022 Subnet Mask = 255.255.255.255
IP Address 00001010 01100100 00000100 00010110
Subnet Mask 11111111 11111111 11111111 11111111
--------------------------------------
Result 00001010 01100100 00000100 00010110
The AND result in decimal is 010.100.004.022. Therefore, this is the
only address that has access to the LU.
IP Address = 131.107.100.001 Subnet Mask = 255.255.240.0
IP Address 10000011 01101011 01100100 00000001
Subnet Mask 11111111 11111111 11110000 00000000
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Result 10000011 01101011 01100000 00000000
The AND result in decimal is 131.107.096.000. Therefore, addresses
131.107.096.001 - 131.107.111.254 have access to the LU.
138086 Windows NT 3.51: Reverse name resolution for WINS clients
Additional query words: HIS 2000 HIS2004
Keywords: kbinfo KB190446