Article ID: 176493
Article Last Modified on 3/14/2006
EXCEPTION_ACCESS_VIOLATION raised, attempting to create symptom dump Initializing symptom dump and stack dump facilities ***BEGIN STACK TRACE*** 0x0042F2C8 in sqlservr.EXE, newlinklock() + 0x0418 0x00433717 in sqlservr.EXE, opendb() + 0x00F7 0x0042ED45 in sqlservr.EXE, check_deadlock() + 0x0675 0x0042EFA8 in sqlservr.EXE, newlinklock() + 0x00F8 0x00423B50 in sqlservr.EXE, dbswriteflush() + 0x0160 0x004229BD in sqlservr.EXE, dbswritecheck() + 0x07AD 0x0040E680 in sqlservr.EXE, ksconsole() + 0x0320 0x0040F1E5 in sqlservr.EXE, initcfgfix() + 0x03D5 0x0040ED45 in sqlservr.EXE, initconfig() + 0x0165 0x0040B7B2 in sqlservr.EXE, SqlDumpLocks() + 0x0052 0x00415217 in sqlservr.EXE, udasyncwrite() + 0x0187
197177 INF: How to Obtain SQL Server 6.5 Service Pack 5a
use pubs go create view v1 AS select ta.title_id, t.pub_id from titleauthor ta inner join titles t on t.title_id = ta.title_id
set forceplan on select distinct * from v1 where pub_id in (select pub_id from publishers) set forceplan off
set forceplan on select distinct v1.* from v1 inner join publishers p on v1.pub_id=p.pub_id set forceplan off
Additional query words: joinorder join order exception
Keywords: kbbug kbfix kbusage KB176493